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Chemical Equilibrium Set 3
Results
#1.
Extent to H2 + I2 ® 2HI can be increased by
increasing pressure
increasing pressure
increasing product
increasing product
increasing temp
increasing temp
adding a catalyst
adding a catalyst
#2.
Strength of an acid can be determined by
PKa
PKa
PKp
PKp
POH
POH
PKw
PKw
#3.
In an exothermic reversible reaction increase in temp shifts the equilibrium to
reactant side
reactant side
product side
product side
remains unchanged
remains unchanged
none
none
#4.
Units of Kw are
mole dm–3
mole dm–3
mole2 dm–3
mole2 dm–3
mole2 dm–6
mole2 dm–6
mole2 dm–3
mole2 dm–3
#5.
A basic Buffer solution can be prepared by mixing
weak acid and its salt with strong base
weak acid and its salt with strong base
strong acid and its salt with weak base
strong acid and its salt with weak base
weak base and its salt with strong acid
weak base and its salt with strong acid
strong base and its salt with weak acid
strong base and its salt with weak acid
#6.
Buffer action can be explained by
common ion effect
common ion effect
law of mass action
law of mass action
Le–Chatlier’s principle
Le–Chatlier’s principle
all above
all above
#7.
Ionization of weak acid is expressed in term of following constant
Kw
Kw
Kn
Kn
Ka
Ka
Kb
Kb
#8.
Solubility of Ca(OH)2 is exothermic. If solubility will increase
at high temp
at high temp
at low temp
at low temp
temp independent
temp independent
none
none
#9.
For which system does the equilibrium constant, Kc has units of concentration
N2 + 3H2 2NH3
N2 + 3H2 2NH3
H2 + I2 2 HI
H2 + I2 2 HI
2NO2 N2O4
2NO2 N2O4
2HF H2 + F2
2HF H2 + F2
#10.
Which statement about the following equilibrium is correct 2SO2(g) + O2(g) 2SO3(g) D H = – 188.3 kJ mol–1
the value of Kp falls with a rise in temp
the value of Kp falls with a rise in temp
the value of Kp falls with increasing pressure
the value of Kp falls with increasing pressure
adding V2O5 catalyst increase the equilibrium yield of sulphur trioxide
adding V2O5 catalyst increase the equilibrium yield of sulphur trioxide
the value of Kp is equal to Kc
the value of Kp is equal to Kc
Finish
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